POKER FANS, TEXAS HOLDEM, WHY IS THE CHANCES OF BEING DEALT A-A 221 to 1 ?

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  1. InterchangePlus

    InterchangePlus
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    (PRE-FLOP) When playing Texas Holdem you are dealt 2 hole cards face down. The number of combinations of starting hands is simply 52×51 then divide by 2 which is a total of 1326 starting hands. The reason why we divide by 2 is to ignore the order in which the cards are dealt e.g Ac-Ad and Ad-Ac same, get it!

    Now, there are 6 combinations of making A-A. e.g {As-Ah} {As-Ad} {As-Ac} {Ah-Ad} {Ah-Ac} and {Ad-Ac}

    So if we divide 1326 by the 6 combinations we get 221! Of course all other pocket pairs are the same calculation. You can say what are the chances of being dealt any pocket pair J-J or above which is 4×6 which is 24 combinations. That would mean that being dealt a starting hand of J-J, Q-Q, K-K or A-A would be 1326 starting hands divided by 24 combinations which would be 55.25 to 1. Also, any non-paired starting hands like A-K has 16 combinations. This would be 1326/16 which would be 82.875 to 1.

    If you have played Texas Holdem before I am sure you have heard the term "Big Slick". Well, actually it is more difficult to get dealt A-K suited "Big Slick Suited" than A-A aka "Pocket Rockets".
    The reason is there are only 4 combinations of getting "Big Slick Suited" e.g. {As-Ks} {Ac-Kc} {Ah-Kh} and {Ad-Kd}. In this case we take 1326/4 and come up with 331.5 to 1.

    Now you can figure out the odds of getting dealt any two hole cards in Texas Holdem!

    Quiz, If I was to ask you what are the odds of being dealt any pocket pair what would the answer be?

    Well, using this system you should come up with 17 to 1.

    The next time you play Texas Holdem as Mike Sexton says "May all your cards be live and your pots be monsters!"
     

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